60x=3x^2+12

Solution for 60x=3x^2+12 equation:

60x=3x^2+12

We move all terms to the left:

60x-(3x^2+12)=0

We get rid of parentheses

-3x^2+60x-12=0

a = -3; b = 60; c = -12;
Δ = b2-4ac
Δ = 602-4·(-3)·(-12)
Δ = 3456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3456}=\sqrt{576*6}=\sqrt{576}*\sqrt{6}=24\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-24\sqrt{6}}{2*-3}=\frac{-60-24\sqrt{6}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+24\sqrt{6}}{2*-3}=\frac{-60+24\sqrt{6}}{-6}
$